(6x-4x^2)+4.1=10

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Solution for (6x-4x^2)+4.1=10 equation: 



(6x-4x^2)+4.1=10

We move all terms to the left:

(6x-4x^2)+4.1-(10)=0

We add all the numbers together, and all the variables

(6x-4x^2)-5.9=0

We get rid of parentheses

-4x^2+6x-5.9=0

a = -4; b = 6; c = -5.9;
Δ = b2-4ac
Δ = 62-4·(-4)·(-5.9)
Δ = -58.4
Delta is less than zero, so there is no solution for the equation

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